document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=147296>Question 147296</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x^2-2x-15=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107665 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107665\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2-2x-15=0<BR>\n" );
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document.write( "Attempt to \"factor\" first<BR>\n" );
document.write( "Failing that, then use the \"quadratic equation\".<BR>\n" );
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document.write( "When factoring:<BR>\n" );
document.write( "ask yourself what two factors of 15 will combine to give you -2.<BR>\n" );
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document.write( "Factors of 15:<BR>\n" );
document.write( "1 15<BR>\n" );
document.write( "3  5<BR>\n" );
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document.write( "Therefore, it would be:<BR>\n" );
document.write( "(x+3)(x-5) = 0<BR>\n" );
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document.write( "To find the solution, set each of the above factors to zero and solve:<BR>\n" );
document.write( "x+3 = 0<BR>\n" );
document.write( "x = -3<BR>\n" );
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document.write( "x-5=0<BR>\n" );
document.write( "x = 5<BR>\n" );
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document.write( "Solution: {0,5}<BR>\n" );
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