document.write( "Question 147290: A tank holds 80 gallons of chemical solution. Currently the solution has a strength of 30%. How much of this should be drained and replaced with a 70% solution to get a final strength of 40%? \n" ); document.write( "
Algebra.Com's Answer #107664 by josmiceli(19441)\"\" \"About 
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Let \"x\"= amount of 30% solution to be drained and replaced with
\n" ); document.write( "70% solution
\n" ); document.write( "Currently, how much chemical is in the 30% solution?
\n" ); document.write( "\".3%2A80+=+24\" gallons
\n" ); document.write( "How much chemical will be in the amount drained off?
\n" ); document.write( "\".3x\"
\n" ); document.write( "Then how much chemical will be in the solution that is put back in?
\n" ); document.write( "\".7x\"
\n" ); document.write( "In words:
\n" ); document.write( "(amount of chemical I end up with) / (amount of solution I end up with) =
\n" ); document.write( "final strength of solution
\n" ); document.write( "\"%2824+-+.3x+%2B+.7x%29+%2F+%2880+-+x+%2B+x%29+=+.4\"
\n" ); document.write( "\"%2824+%2B+.4x%29+%2F+80+=+.4\"
\n" ); document.write( "\"24+%2B+.4x+=+.4%2A80\"
\n" ); document.write( "\"24+%2B+.4x+=+32\"
\n" ); document.write( "\".4x+=+8\"
\n" ); document.write( "\"x+=+20\"
\n" ); document.write( "20 gallons must be drained off and replaced with 70% solution
\n" ); document.write( "check answer:
\n" ); document.write( "\"%2824+%2B+.4x%29+%2F+80+=+.4\"
\n" ); document.write( "\"24+%2B+.4%2A20%29+%2F+80+=+.4\"
\n" ); document.write( "\"24+%2B+8%29+%2F+80+=+.4\"
\n" ); document.write( "\"32%2F80+=+.4\"
\n" ); document.write( "\"32+=+32\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );