document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=147249>Question 147249</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of an rectangle is fixed at 20 cm. what widths will make the perimiter greater than 86 cm? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107626 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107626\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter of a rectangle = 2 x (Length + Width)\r<BR>\n" );
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document.write( "Let width = w cm.<BR>\n" );
document.write( "Then the perimeter = 2(20 + w) = (40 + 2w) cm.<BR>\n" );
document.write( "By problem this perimeter has to be greater than 86 cm.<BR>\n" );
document.write( "So, 40 + 2w > 86.<BR>\n" );
document.write( "2w > 86 - 40<BR>\n" );
document.write( "2w > 46<BR>\n" );
document.write( "w > 23\r<BR>\n" );
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document.write( "So, the width has to be more than 23 cm. </SPAN>\n" );
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