document.write( "Question 22248: Good Afternoon, I am trying to work out some problems but I don't know what I am doing. Can someone please help me? Here is the question. \r
\n" ); document.write( "\n" ); document.write( "log8x=2/3
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Algebra.Com's Answer #10761 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve for x:
\n" ); document.write( "\"log%28%288x%29%29+=+2%2F3\" Apply the product rule for logaritms: log\"b\"MN = log\"b\"M + log\"b\"N
\n" ); document.write( "\"log%28%288x%29%29+=+log%28%288%29%29+%2B+log%28%28x%29%29\" So:
\n" ); document.write( "\"log%28%288%29%29+%2B+log%28%28x%29%29+=+2%2F3\" Subtract log(8) from both sides.
\n" ); document.write( "\"log%28%28x%29%29+=+2%2F3+-+log%28%288%29%29\" Rewrite in exponential form: log\"b\"x = y means b^y = x
\n" ); document.write( "\"x+=+10%5E%28%282%2F3-log8%29%29\" You can do this on your calculator.
\n" ); document.write( "\"x+=+0.5801986\"\r
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "\"log%28%288%280.5801986%29%29%29+=+0.666666\"
\n" ); document.write( "\"2%2F3+=+0.666666\"
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