document.write( "Question 2547: The sum of Jane's age and Jim's age is 40. Jane's age 10 years from now will be 1 year less than 4 times Jim's age 6 years ago. Find their ages. \n" ); document.write( "

Algebra.Com's Answer #1076 by kiru_khandelwal(79) $\"\"$ $\"About$

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Let Jane's age now be x and jim's age now be y
\n" ); document.write( "So,
\n" ); document.write( "x+y = 40 ...........(1)
\n" ); document.write( "10 yrs from now Jane's age = x+10
\n" ); document.write( "Jim's age 6 yrs ago = y-6
\n" ); document.write( "Jane's age 10 years from now will be 1 year less than 4 times Jim's age 6 years ago, so
\n" ); document.write( "x+10 = 4(y-6)-1 .............(2)\r
\n" ); document.write( "\n" ); document.write( "Now we have two equations:\r
\n" ); document.write( "\n" ); document.write( "x+y = 40 and x+10= 4(y-6)-1\r
\n" ); document.write( "\n" ); document.write( "From Ist equation :
\n" ); document.write( "x = 40-y..................(3)\r
\n" ); document.write( "\n" ); document.write( "Substituting the value of x in IInd equation:
\n" ); document.write( "x+10=4(y-6)-1
\n" ); document.write( "(40-y)+10=4(y-6)-1
\n" ); document.write( "40-y+10=4(y-6)-1
\n" ); document.write( "50-y=4y-24-1
\n" ); document.write( "50-y=4y-25
\n" ); document.write( "50+25 = 4y+y
\n" ); document.write( "75=5y
\n" ); document.write( "5y=75
\n" ); document.write( "y=75/5
\n" ); document.write( "y=15
\n" ); document.write( "So, Jim's age = 15
\n" ); document.write( "Now , x=40-y ....From (3)
\n" ); document.write( "So, x = 40-15 = 25\r
\n" ); document.write( "\n" ); document.write( "Answer,
\n" ); document.write( "Jane's age = 25
\n" ); document.write( "Jim's age = 15 \n" ); document.write( "

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