document.write( "Question 147227: Explain how the quadratic formula can be used to factor a quadratic polynomial into two binomials using this equation. I am not so interested in the solution as I am interested in the explanation of the steps in factoring this equation into two binomials.
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Algebra.Com's Answer #107598 by jim_thompson5910(35256) $\"\"$ $\"About$

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It turns out that the solutions to any quadratic will form the factors of the quadratic itself. So let's say that we want to factor $\"x%5E2%2B5x%2B6\"$ . We know that this factors to $\"%28x%2B3%29%28x%2B2%29\"$ . But if we didn't know that, we can use the quadratic formula to find the solutions $\"x=-3\"$ and $\"x=-2\"$ . From there, we need to get all terms to one side to get $\"x%2B3=0\"$ and $\"x%2B2=0\"$ . Now just combine the two equations into one like this $\"%28x%2B3%29%28x%2B2%29=0\"$ (note: this is using the zero product property in reverse). \n" ); document.write( "

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