document.write( "Question 146917: A man invests a portion of $3,600 at 8% annual interest and the balance at 7%. If he receives $264 interest during the first year, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #107580 by edjones(8007)\"\" \"About 
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Let x=amount invested at 8%, 3600-x=amount invested at 7%
\n" ); document.write( ".08x+.07(3600-x)=264
\n" ); document.write( ".08x+252-.07x=264
\n" ); document.write( ".01x=12
\n" ); document.write( "x=$1200.
\n" ); document.write( "3600-x=$2400.
\n" ); document.write( ".
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