document.write( "Question 146917: A man invests a portion of $3,600 at 8% annual interest and the balance at 7%. If he receives $264 interest during the first year, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #107580 by edjones(8007)![]() ![]() You can put this solution on YOUR website! Let x=amount invested at 8%, 3600-x=amount invested at 7% \n" ); document.write( ".08x+.07(3600-x)=264 \n" ); document.write( ".08x+252-.07x=264 \n" ); document.write( ".01x=12 \n" ); document.write( "x=$1200. \n" ); document.write( "3600-x=$2400. \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |