document.write( "Question 146929: Solve system using elimination method
\n" ); document.write( "x^2+3y=25
\n" ); document.write( "x+y=7 \n" ); document.write( "

Algebra.Com's Answer #107575 by mangopeeler07(462) $\"\"$ $\"About$

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Since you have a squared variable, you will get two answers for both x and y. First multiply the second equation by -3 and get $\"-3x-3y=-21\"$ . Add that to the first equation and get $\"x%5E2-3x=4\"$ . Move 4 over to the left by subtracting it from both sides and get $\"x%5E2-3x-4=0\"$ . Factor it out and get $\"%28x%2B1%29%28x-4%29=0\"$ . Then plug in the values of x that make that true. Those would be -1 and 4, because if you plug those in, you end up with zero. Then go back to either of the first two original equations and plug both x values in. The answer you get after plugging in each values is your y value. You should get y=8 and 3. (8 when x=-1 and 3 when x=4). Therefore x=-1;4 and y=8;3. \n" ); document.write( "

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