document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=146915>Question 146915</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi I need your help. Three consecutive odd integers are such that the square of the third is 264 more than the square of the second. Find the three integers. I'm trying to understand how you would write this out to be able to work it. Thank you, Reuben </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107567 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107567\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the integers be x, x+2, x+4<BR>\n" );
document.write( "(x+4)^2=(x+2)^2+264<BR>\n" );
document.write( "x^2+8x+16=x^2+4x+4+264<BR>\n" );
document.write( "4x-252=0 subtract the right side from the left.<BR>\n" );
document.write( "4x=252<BR>\n" );
document.write( "x=63<BR>\n" );
document.write( "63, 65, 67 are the integers.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );