document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=146949>Question 146949</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Make up a geometry problem to go with the equation<BR>\n" );
document.write( "x + 3x + (x to the square root of 10) = 42.\r<BR>\n" );
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document.write( "I think it has to do with a triangle but I'm not sure. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107528 by </B><A HREF=/tutors/aboutme.mpl?userid=mangopeeler07><B>mangopeeler07(462)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mangopeeler07><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107528\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Actually, this does not have to be a triangle.  First draw a shape.  How about a rectangle?  Draw the rectangle.  Then on the top, mark the length as 42.  Then by drawing two straight lines from the top to the bottom of the rectangle, divide the rectangle into three parts.  The top line is still marked as 42.  Mark the segments of the bottom line (the segments where the vertical lines divide) as <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+sqrt%2810%29 ALIGN=MIDDLE  ALT=\"x+sqrt%2810%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x ALIGN=MIDDLE  ALT=\"3x\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x ALIGN=MIDDLE  ALT=\"x\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  So the bottom side is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+sqrt%2810%29 ALIGN=MIDDLE  ALT=\"x+sqrt%2810%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x ALIGN=MIDDLE  ALT=\"3x\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x ALIGN=MIDDLE  ALT=\"x\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Since one property of a rectangles is that the opposite sides are congruent, then by drawing this, you have illustrated that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+sqrt%2810%29 ALIGN=MIDDLE  ALT=\"x+sqrt%2810%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x ALIGN=MIDDLE  ALT=\"3x\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x ALIGN=MIDDLE  ALT=\"x\"   DISABLED_style= \"max-width:90%; height:auto;\" > is congruent to 42 (the top side).  And there you have it! No sweat, right? </SPAN>\n" );
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