document.write( "Question 147165: solve using the addition method,answer must be an ordered pair.
\n" ); document.write( "-2x=2y+5
\n" ); document.write( "6x+3y=3
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Algebra.Com's Answer #107497 by mangopeeler07(462)\"\" \"About 
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Choose a variable to solve for first. How about y? Line up the two equations and multiply \"-2x=2y%2B5\" by three. Then manipulate the second equation into \"6x=-3y%2B3\" by subtracting 3y from both sides. Once this is done, you should have \"-6x=6y%2B15\" and \"6x=-3y%2B3\". Add them together and get \"0=3y%2B18\". Subtract 18 from both sides and get \"-18=3y\". Divide both sides by three and get y=-6. Then plug y back into the original equation \"-2x=2y%2B5\" and solve for x. \"-2x=-12%2B5\" after plugging in y, and get \"-2x=-7\". Divide each side by -2 and get \"x=7%2F2\". You wanna check? Plug x and y into \"6x%2B3y%2B3\". Get \"21-18=3\". It's true! So y=-6 and x=7/2. \n" ); document.write( "
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