document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=147150>Question 147150</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A small area in front of a building is triangular in shape.  The perimeter of the triangle is 37 meters. The second side is one-half of the first side in length. The third side is 3 meters less than the first side. Find the length in meters of each side of the triangular region. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107476 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107476\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of the triangle is 37 meters. The second side is one-half of the first side in length. The third side is 3 meters less than the first side. Find the length in meters of each side of the triangular region.<BR>\n" );
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document.write( "Let x = length of 1st side<BR>\n" );
document.write( "x/2 = length of 2nd side<BR>\n" );
document.write( "x-3 = length of 3rd side<BR>\n" );
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document.write( "The sum of the sides = perimeter<BR>\n" );
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document.write( "x + x/2 + (x-3) = 37<BR>\n" );
document.write( "2x + x/2 = 40<BR>\n" );
document.write( "4x + x = 80<BR>\n" );
document.write( "5x = 80<BR>\n" );
document.write( "x = 16 meters(1st side)<BR>\n" );
document.write( "x/2 = 8 meters (2nd side)<BR>\n" );
document.write( "x-3 = 15 meters (3rd side) </SPAN>\n" );
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