document.write( "Question 147127: I am attempting to solve two equations using the substitution method.\r
\n" ); document.write( "\n" ); document.write( "x + y = 56 first equation\r
\n" ); document.write( "\n" ); document.write( "I have 3 times as many y as x, so I believe the next equation is\r
\n" ); document.write( "\n" ); document.write( "3x + y = 56
\n" ); document.write( " solve for y
\n" ); document.write( "y = -3x + 56 now in the first equation, I replace y with -3x + 56\r
\n" ); document.write( "\n" ); document.write( "x + -3x +56 =56
\n" ); document.write( "-2x + 56 -56 = 56 -56
\n" ); document.write( "-2x = 0? This can not be correct. Can you help me?\r
\n" ); document.write( "\n" ); document.write( "Thank you very much.\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #107461 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
x + y = 56 first equation
\n" ); document.write( "I have 3 times as many y as x, so the next equation is
\n" ); document.write( "y = 3x
\n" ); document.write( ":
\n" ); document.write( "Substitute 3x for y in the 1st equation
\n" ); document.write( "x + 3x = 56
\n" ); document.write( "4x = 56
\n" ); document.write( "x = $\"56%2F4\"$
\n" ); document.write( "x = 14
\n" ); document.write( ":
\n" ); document.write( "Does this explain it? \n" ); document.write( "

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