document.write( "Question 147112: Alan and Dave leave from the same point driving in opposite directions, Alan driving at 55 miles per hour and Dave 65 mph. Alan has a one hour head start. How long will they be able to talk on their car phones if the phones have a 250-mile range? \n" ); document.write( "
Algebra.Com's Answer #107453 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Restated, the problem is, when will the sum of their
\n" ); document.write( "distances from the starting point exceed 250 mi?
\n" ); document.write( "Assume I have a stopwatch. I will start the stopwatch
\n" ); document.write( "when Alan has already driven foor 1 hr.
\n" ); document.write( "By then, Alan has driven \"d%5Ba%5D+=+55%2A1\"
\n" ); document.write( "\"d%5Ba%5D+=+55\"mi
\n" ); document.write( "I want to find \"d%5Ba%5D+%2B+d%5Bd%5D+=+250\"
\n" ); document.write( "But now, \"d%5Ba%5D\", Allan's distance from the starting
\n" ); document.write( "point is \"r%5Ba%5D%2At+%2B+55\" where \"t\" is the time
\n" ); document.write( "showing on my stopwatch.
\n" ); document.write( "Now I can write \"r%5Ba%5D%2At+%2B+55+%2B+r%5Bd%5D%2At+=+250\"
\n" ); document.write( "\"55t+%2B+55+%2B+65t+=+250\"
\n" ); document.write( "\"120t+=+190\"
\n" ); document.write( "\"t+=+12%2F19\" hr
\n" ); document.write( "\"t+=+.6316\"hr
\n" ); document.write( "This is the time after Alan's 1 hr headstart, so they can
\n" ); document.write( "talk on their cellphones for
\n" ); document.write( "\"t+=+1.6316\" hr
\n" ); document.write( "t = 1 hr 37.895 min
\n" ); document.write( "t = 1 hr 37 min 54 sec answer
\n" ); document.write( "That's it, unless I goofed.
\n" ); document.write( "check:
\n" ); document.write( "\"55t+%2B+55+%2B+65t+=+250\"
\n" ); document.write( "\"55%2A1.632+%2B+55+%2B+65%2A1.632+=+250\"
\n" ); document.write( "\"89.76+%2B+55+%2B+106.08+=+250\"
\n" ); document.write( "\"250.84+=+250\"
\n" ); document.write( "pretty close
\n" ); document.write( "
\n" );