document.write( "Question 147100: In Triangle ABC, it is given that CA=CB. Points P and Q are marked on segments CA and CB respectively, so that angles CBP and CAQ are the same size. Prove that CP=CQ.
\n" ); document.write( "Thank you.
\n" ); document.write( "

Algebra.Com's Answer #107442 by Edwin McCravy(20064)\"\" \"About 
You can put this solution on YOUR website!
In Triangle ABC, it is given that CA=CB. Points P and Q are marked on segments CA and CB respectively, so that angles CBP and CAQ are the same size. Prove that CP=CQ.
\n" ); document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "ÐCBP = ÐCAQ      Given\r\n" );
document.write( "\r\n" );
document.write( "  CA = CB        Given \r\n" );
document.write( "\r\n" );
document.write( "  ÐC = ÐC        Identity\r\n" );
document.write( "\r\n" );
document.write( "DCBP @ DCAQ      Angle-Side-Angle\r\n" );
document.write( "\r\n" );
document.write( "  CP = CQ        Corresponding parts of congruent triangles\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );