document.write( "Question 147094: Brian and Jake left their homes, which are 500 miles apart, and drove straight toward each other. It took 4 hours for the two to meet. If Jake's speed was 15 mph slower than Brian's speed, what was Brian's speed? \n" ); document.write( "
Algebra.Com's Answer #107431 by checkley77(12844)\"\" \"About 
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4X+4(X-15)=500
\n" ); document.write( "4X+4X-60=500
\n" ); document.write( "8X=500+60
\n" ); document.write( "8X=560
\n" ); document.write( "X=560/8
\n" ); document.write( "X=70 MPH FOR THE BRIAN'S SPEED.
\n" ); document.write( "70-15=55 FOR JEFF'S SPEED
\n" ); document.write( "PROOF:
\n" ); document.write( "4*70+4*55=500
\n" ); document.write( "280+220=500
\n" ); document.write( "500=500
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