document.write( "Question 147094: Brian and Jake left their homes, which are 500 miles apart, and drove straight toward each other. It took 4 hours for the two to meet. If Jake's speed was 15 mph slower than Brian's speed, what was Brian's speed? \n" ); document.write( "
Algebra.Com's Answer #107431 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 4X+4(X-15)=500 \n" ); document.write( "4X+4X-60=500 \n" ); document.write( "8X=500+60 \n" ); document.write( "8X=560 \n" ); document.write( "X=560/8 \n" ); document.write( "X=70 MPH FOR THE BRIAN'S SPEED. \n" ); document.write( "70-15=55 FOR JEFF'S SPEED \n" ); document.write( "PROOF: \n" ); document.write( "4*70+4*55=500 \n" ); document.write( "280+220=500 \n" ); document.write( "500=500 \n" ); document.write( " \n" ); document.write( " |