document.write( "Question 147090: I need help on how to solve this word problem.
\n" ); document.write( "(((The area of triangle is 462m^2 if the altitude is 2m longer than half the base find the altitude and base of the triangle.))) \n" ); document.write( "

Algebra.Com's Answer #107430 by checkley77(12844) $\"\"$ $\"About$

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AREA=B*H/2
\n" ); document.write( "462=B(B/2+2)/2
\n" ); document.write( "462=[B(B+4)/2]/2
\n" ); document.write( "462=(B^2+4B)/2*1/2
\n" ); document.write( "462=(B^2+4B)/4
\n" ); document.write( "4*462=B^2+4B
\n" ); document.write( "1,848=B^2+4B
\n" ); document.write( "B^2+4B-1,848=0
\n" ); document.write( "USING THE QUADRATIC EQUATION: $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "B=(-4+-SQRT4^2-4*1*-1848})/281
\n" ); document.write( "B=(-4+-SQRT[16+7,392])/2
\n" ); document.write( "B=(-4+-SQRT7,408)/2
\n" ); document.write( "B=(-4+-86.07)/2
\n" ); document.write( "B=(-4+86.07)/2
\n" ); document.write( "82.07/2
\n" ); document.write( "B=41.03 FOR THE LENGTH OF THE BASE
\n" ); document.write( "H=2+41.03/2=2+20.52=22.52 FOR THE HEIGHT
\n" ); document.write( "PROOF
\n" ); document.write( "462=41.03*22.52/2
\n" ); document.write( "462~462 \n" ); document.write( "

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