document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=147089>Question 147089</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have been out of high school and college for over 4 years now...so I used to know the answer, but we are far from it now!  I am looking for the \"rules\" or \"formula\" or \"whatever\" that makes this a correct statement.  You have a triangle with a right angle.  Side A =3ft Side B=4ft  (side A and B are connected by the right angle).  We know that side C (the hypotonus) =5ft.  I want this equation in a larger term (ie Side A=10ft Side B=20ft what is side C)  Thanks so much for your help!  I actually miss doing this on a regular basis!  I loved math in high school, and now it just helping my dad build a cabin.  Thanks again.  Michelle Wagner </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107421 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107421\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the Pythagorean Theorem.  For a right triangle where the legs are <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a ALIGN=MIDDLE  ALT=\"a\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b ALIGN=MIDDLE  ALT=\"b\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and the hypotenuse is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c ALIGN=MIDDLE  ALT=\"c\"   DISABLED_style= \"max-width:90%; height:auto;\" >, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c%5E2=a%5E2%2Bb%5E2 ALIGN=MIDDLE  ALT=\"c%5E2=a%5E2%2Bb%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, so <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c=sqrt%28a%5E2%2Bb%5E2%29 ALIGN=MIDDLE  ALT=\"c=sqrt%28a%5E2%2Bb%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "For your example:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=10 ALIGN=MIDDLE  ALT=\"a=10\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b=20 ALIGN=MIDDLE  ALT=\"b=20\"   DISABLED_style= \"max-width:90%; height:auto;\" >, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c=sqrt%28%2810%29%5E2%2B%2820%29%5E2%29=sqrt%28100%2B400%29=sqrt%28500%29 ALIGN=MIDDLE  ALT=\"c=sqrt%28%2810%29%5E2%2B%2820%29%5E2%29=sqrt%28100%2B400%29=sqrt%28500%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > roughly 22.36 feet or about 22 feet, 4 and 3/8 inches.  That ought to be close enough for log cabin building.\r<BR>\n" );
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document.write( "To do the decimal to feet/inches conversion, take the decimal part of the measurement and multiply times 12.  .36 X 12 = 4.328 roughly.  Now compare the decimal part of that result to the following table:\r<BR>\n" );
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document.write( "1/8 = .125<BR>\n" );
document.write( "1/4 = .250<BR>\n" );
document.write( "3/8 = .375<BR>\n" );
document.write( "1/2 = .500<BR>\n" );
document.write( "5/8 = .625<BR>\n" );
document.write( "3/4 = .750<BR>\n" );
document.write( "7/8 = .875\r<BR>\n" );
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document.write( "Pick the decimal value closest to the decimal part of your calculation and use the corresponding fractional value.  That gets you within 1/8 inch which should be close enough.  .328 corresponds most closely with .375, so 3/8 inch.  Putting it all back together:  22 feet, 4 and 3/8 inches.\r<BR>\n" );
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document.write( "Hope that helps </SPAN>\n" );
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