document.write( "Question 147088: I need to solve using quadratic formula 2x^2-3x=-6 the solution set is { }
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document.write( "what I am coming up with is
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document.write( "-(-3)+-sqrt57/4
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document.write( "but I am stuck after that
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document.write( "any help would be appreciated! Thank you \n" );
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Algebra.Com's Answer #107412 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! I need to solve using quadratic formula 2x^2-3x=-6 the solution set is { } \n" ); document.write( "what I am coming up with is \n" ); document.write( "-(-3)+-sqrt57/4 \n" ); document.write( "but I am stuck after that \n" ); document.write( "------------------------------\r \n" ); document.write( "\n" ); document.write( "2x^2-3x=-6 \n" ); document.write( "2x^2-3x+6 = 0 \n" ); document.write( "a = 2 ; b = -3 ; c = 6 \n" ); document.write( "--------- \n" ); document.write( "x = [3 +- sqrt(3 -4*2*6]/4\r \n" ); document.write( "\n" ); document.write( "x = [3 +- sqrt(-45)]/4\r \n" ); document.write( "\n" ); document.write( "x = [3 +- 3isqrt(5)]/4\r \n" ); document.write( "\n" ); document.write( "x = (3/4)[1+isqrt(5)] or x = (3/4)[1 - isqrt(5)] \n" ); document.write( "========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |