document.write( "Question 147088: I need to solve using quadratic formula 2x^2-3x=-6 the solution set is { }
\n" ); document.write( "what I am coming up with is
\n" ); document.write( "-(-3)+-sqrt57/4
\n" ); document.write( "but I am stuck after that
\n" ); document.write( "any help would be appreciated! Thank you
\n" ); document.write( "

Algebra.Com's Answer #107412 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
I need to solve using quadratic formula 2x^2-3x=-6 the solution set is { }
\n" ); document.write( "what I am coming up with is
\n" ); document.write( "-(-3)+-sqrt57/4
\n" ); document.write( "but I am stuck after that
\n" ); document.write( "------------------------------\r
\n" ); document.write( "\n" ); document.write( "2x^2-3x=-6
\n" ); document.write( "2x^2-3x+6 = 0
\n" ); document.write( "a = 2 ; b = -3 ; c = 6
\n" ); document.write( "---------
\n" ); document.write( "x = [3 +- sqrt(3 -4*2*6]/4\r
\n" ); document.write( "\n" ); document.write( "x = [3 +- sqrt(-45)]/4\r
\n" ); document.write( "\n" ); document.write( "x = [3 +- 3isqrt(5)]/4\r
\n" ); document.write( "\n" ); document.write( "x = (3/4)[1+isqrt(5)] or x = (3/4)[1 - isqrt(5)]
\n" ); document.write( "==========
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
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