document.write( "Question 147020: Solve the following word problems:\r
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document.write( "A: Tina can run 12 miles in the same time it takes her ti bicycle 72 miles. If her bicycling rate is 20 miles/hour faster than her running rate, find each rate.\r
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document.write( "B: Kevin earned $165 interest for 1 year on investment of $1500. At the same rate, what amount of interest would be earned by an investment of $2500? \n" );
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Algebra.Com's Answer #107410 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A: Tina can run 12 miles in the same time it takes her to bicycle 72 miles. If her bicycling rate is 20 miles/hour faster than her running rate, find each rate. \n" ); document.write( ": \n" ); document.write( "Let s = T's running speed \n" ); document.write( "then \n" ); document.write( "(s+20) = T's biking speed \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = \n" ); document.write( "Time to Bike 72 mi = Time to run 12 mi \n" ); document.write( " \n" ); document.write( "Cross multiply, find s: \n" ); document.write( ": \n" ); document.write( "72s = 12(s+20) \n" ); document.write( ": \n" ); document.write( "72s = 12s + 240 \n" ); document.write( ": \n" ); document.write( "72s - 12x = 240 \n" ); document.write( "s = \n" ); document.write( "s = 4 mph is T's running speed \n" ); document.write( "and \n" ); document.write( "24 mph is T's biking speed \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solutions to see if the times are equal \n" ); document.write( "72/24 = 3 hrs \n" ); document.write( "12/4 = 3 hrs \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "B: Kevin earned $165 interest for 1 year on investment of $1500. At the same rate, what amount of interest would be earned by an investment of $2500? \n" ); document.write( ": \n" ); document.write( "Using the interest formula PRT = I; here t = 1 so it is just: \n" ); document.write( "1500R = 165 \n" ); document.write( "R = \n" ); document.write( "R = .11 or 11% interest \n" ); document.write( ": \n" ); document.write( "For $2500 at 11% \n" ); document.write( ".11 * 2500 = $275 \n" ); document.write( ": \n" ); document.write( "You can also use ratio: (x = interest amt on $2500)) \n" ); document.write( " \n" ); document.write( "1500x = 165 * 2500 \n" ); document.write( "x = \n" ); document.write( "x = $275 \n" ); document.write( " \n" ); document.write( " |