document.write( "Question 147060: Determine the quadradic function, whose graph is given?
\n" ); document.write( "vertex (-2,2)
\n" ); document.write( "y-intercept (0,-6)
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Algebra.Com's Answer #107408 by giveback(3)\"\" \"About 
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Quadratic function has the generic form as: y=ax^2+bx+c
\n" ); document.write( "Our purpose is to find a, b and c.
\n" ); document.write( "With information given as:
\n" ); document.write( " y-intercept is (0,-6) then we have: -6=a(0)^2+b(0)+c
\n" ); document.write( " from there we have c=-6 (we found c)
\n" ); document.write( " vertex is (-2,2) then we have 2=a(-2)^2+b(-2)-6 or 2a-b=4
\n" ); document.write( " with vertex at (-2,2) we aslo have the line of symmetry as x=-2
\n" ); document.write( " meaning as x=-4, y=-6 then -6=a(-4)^2+b(-4)-6 or 4a-b=0 or b=4a
\n" ); document.write( " substitute b=4a into the equation 2a-b=4 we have 2a-4a=4 or a=-2 (we found a)
\n" ); document.write( " substitute a=-2 into the equation b=4a we find b=-8 (we found b)
\n" ); document.write( "Then our quadratic function is: y=-2x^2-8x-6
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