document.write( "Question 147022: Add or subtract the fractions. Express the answer in simplest form:\r
\n" ); document.write( "\n" ); document.write( "A: [4/(x-2)]+[3/x^2-x-2]\r
\n" ); document.write( "\n" ); document.write( "B: [4y/(y^2+6y+5)]-[2y/(y^2-1)]
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Algebra.Com's Answer #107404 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
A: \"%284%2F%28x-2%29%29%2B%283%2F%28x%5E2-x-2%29%29+\"
\n" ); document.write( "Remember, to add or subtract fractions you need a common denominator.
\n" ); document.write( "Luckily,
\n" ); document.write( "\"x%5E2-x-2=%28x-2%29%28x%2B1%29\"
\n" ); document.write( "So you can multiply, the first term by (x+1)/(x+1) to get it done.
\n" ); document.write( "A: \"%284%2F%28x-2%29%29%2B%283%2F%28x%5E2-x-2%29%29+\"
\n" ); document.write( "A: \"%284%28x%2B1%29%2F%28%28x-2%29%2A%28x%2B1%29%29%29%2B%283%2F%28%28x-2%29%2A%28x%2B1%29%29%29\"
\n" ); document.write( "A: \"%284x%2B4%2B3%29%2F%28%28x-2%29%2A%28x%2B1%29%29+\"
\n" ); document.write( "A: \"%284x%2B7%29%2F%28%28x-2%29%2A%28x%2B1%29%29+\"
\n" ); document.write( "B: \"4y%2F%28y%5E2%2B6y%2B5%29-2y%2F%28y%5E2-1%29\"
\n" ); document.write( "Let's look at both denominators and factor them.
\n" ); document.write( "First term denominator:
\n" ); document.write( "\"y%5E2%2B6y%2B5=%28y%2B5%29%28y%2B1%29\"
\n" ); document.write( "Second term denominator:
\n" ); document.write( "\"y%5E2-1=%28y%2B1%29%28y-1%29\"
\n" ); document.write( "Multiply the first term by (y-1)/(y-1) and
\n" ); document.write( "then multiply the second term by (y+5)/(y+5) to get
\n" ); document.write( "the common denominator (y+1)(y-1)(y+5).
\n" ); document.write( "B:
\n" ); document.write( "B: \"%284y%5E2-4y-2y%5E2-10y%29%2F%28%28y%2B1%29%28y-1%29%28y%2B5%29%29\"
\n" ); document.write( "B: \"%282y%5E2-14y%29%2F%28%28y%2B1%29%28y-1%29%28y%2B5%29%29\"
\n" ); document.write( "B: \"2y%28y-7%29%2F%28%28y%2B1%29%28y-1%29%28y%2B5%29%29\"
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