document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=147061>Question 147061</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Harry is 4 years older then Marvin.  In six years Marvin will be 5/6 as old as Harry.  How old is each boy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107391 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107391\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=Marvin's age now (x+6=Marvin's age six years from now)<BR>\n" );
document.write( "Then x+4=Harry's age now (x+4+6=x+10=Harry's age six years from now)\r<BR>\n" );
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document.write( "So, our equation to solve is:<BR>\n" );
document.write( "x+6=5/6(x+10) multiply each term by 6 and also get rid of parens\r<BR>\n" );
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document.write( "6x+36=5x+50 subtract 36 and also 5x from each side\r<BR>\n" );
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document.write( "6x-5x+36-36=5x-5x+50-36  collect like terms\r<BR>\n" );
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document.write( "x=14---------------------------Marvin's age now\r<BR>\n" );
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document.write( "x+4=14+4=18-------------------Harry's age now\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "18 is 4 more that 14<BR>\n" );
document.write( "and<BR>\n" );
document.write( "14+6=5/6(18+6)<BR>\n" );
document.write( "20=20\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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