document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=147019>Question 147019</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve following word problems:\r<BR>\n" );
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document.write( "A: One number is 3 times another. If the sum of their reciprocals is 1/6, find the two numbers.\r<BR>\n" );
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document.write( "B: If one-third of a number is subtracted from three-fourths of that number, the difference is 15. What is the number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107385 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107385\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a=3b<BR>\n" );
document.write( "1/a + 1/b = 1/6<BR>\n" );
document.write( "1/3b + 1/b = 1/6 substitute<BR>\n" );
document.write( "2+6=b Multiply each side by 6b to eliminate fractions.<BR>\n" );
document.write( "b=8<BR>\n" );
document.write( "a=24<BR>\n" );
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document.write( "Let x be the number.<BR>\n" );
document.write( "3x/4 - x/3 = 15<BR>\n" );
document.write( "9x-4x=180 Multiply each side by 12 to eliminate fractions.<BR>\n" );
document.write( "5x=180<BR>\n" );
document.write( "x=36<BR>\n" );
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document.write( "Ed<BR>\n" );
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