document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=147046>Question 147046</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is one more than twice it's width. If the perimeter is 74inches, find the dimensions of the rectangle.<BR>\n" );
document.write( "I have tried to us this: Given: p=2w+1, p=74, 2p+2l=74. Find: p=perimeter, and w=width. Equation:P=2l+2w. Work: P=2l+2W. 74=2l+2W: 74=2w+1. 73=2w. w=36.5. <BR>\n" );
document.write( "74=2l+2*36.5. 74=2l+73. 1=2L.1=L. Length=1 inch. Width=36.5inches.<BR>\n" );
document.write( "My friends say I am wrong. The width CAN NOT be longer than the length. Are they correct? If so, then what are the correct answers? If the answers are correct, but the problem is wrong. How would the problem be changed to make it right? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107377 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107377\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=2w+2L<BR>\n" );
document.write( "P=2w+1<BR>\n" );
document.write( "so 2L=1<BR>\n" );
document.write( "L=1/2 inch<BR>\n" );
document.write( "2w + (2 * 1/2)=74<BR>\n" );
document.write( "2w=73<BR>\n" );
document.write( "w=36.5 inches<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );