document.write( "Question 147039: Mr. Joyce inherited a sum of money. He invested 2/5 of this sum at 4%, 1/3 at 5%, and the rest at 3%. If the annual income from these investments was $610, find the amount of money he inherited.
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Algebra.Com's Answer #107364 by checkley77(12844)\"\" \"About 
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.04*2X/5+.05*X/3+.03*4/15=610
\n" ); document.write( ".08X/5+.05X/3+.12X/15=610
\n" ); document.write( "(.08X*3+.05X*5+.12X)/15=610
\n" ); document.write( "(.24X+.25X+12X)/15=610
\n" ); document.write( ".61X=15*610
\n" ); document.write( ".61X=9150
\n" ); document.write( "X=9150/.61
\n" ); document.write( "X=$15,000 TOTAL AMOUNT INVESTED.
\n" ); document.write( "PROOF:
\n" ); document.write( ".08*15000/5+.05*15000/3+.12*15,000/15=610
\n" ); document.write( "240+250+120=610
\n" ); document.write( "610=610\r
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