document.write( "Question 147027: I really need help with solving a system using the elimination method. Please!
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document.write( "x^2+3y=25
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document.write( "x+y=7 \n" );
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Algebra.Com's Answer #107363 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! x^2 + 3y = 25 \n" ); document.write( "x + y = 7 \n" ); document.write( ": \n" ); document.write( "Multiply the 2nd equation by 3 and subtract from the 1st equation: \n" ); document.write( "x^2 + 3y = 25 \n" ); document.write( "3x + 3y = 21 \n" ); document.write( "---------------Subtracting eliminates y, leaving us with \n" ); document.write( "x^2 + 3x = 4 \n" ); document.write( ": \n" ); document.write( "A quadratic equation that we can factor: \n" ); document.write( "x^2 + 3x - 4 = 0 \n" ); document.write( "(x + 4)(x - 1) = 0 \n" ); document.write( "Two solutions: \n" ); document.write( "x = -4 \n" ); document.write( "x = +1 \n" ); document.write( ": \n" ); document.write( "Find the value for y using both solutions using the 2nd equation (x + y = 7) \n" ); document.write( "x=-4 \n" ); document.write( "-4 + y = 7 \n" ); document.write( "y = 7 + 4 \n" ); document.write( "y = 11 \n" ); document.write( "and \n" ); document.write( "x = +1 \n" ); document.write( "1 + y = 7 \n" ); document.write( "y = 7 - 1 \n" ); document.write( "y = 6 \n" ); document.write( ": \n" ); document.write( "We have two sets of solutions: x=-4,y=11 and x=1,y=6 \n" ); document.write( ": \n" ); document.write( "But only one set will work in the 1st equation, substitute both in x^2 + 3y = 25 \n" ); document.write( "You do this and you will see that x=1;y=6 is the solution that satisfies both equations. \n" ); document.write( " \n" ); document.write( " |