document.write( "Question 147023: The length of a rectangle is two more than three times the width.If the perimeter is 100, find the length and width of the rectangle.\r
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Algebra.Com's Answer #107361 by nerdybill(7384)\"\" \"About 
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The length of a rectangle is two more than three times the width.If the perimeter is 100, find the length and width of the rectangle.
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\n" ); document.write( "Let W = width of rectangle
\n" ); document.write( "then from \"length of a rectangle is two more than three times the width\" we get
\n" ); document.write( "3W+3 = length of rectangle
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\n" ); document.write( "Our equation comes from \"the perimeter is 100\"
\n" ); document.write( "We \"should\" already know that the perimeter of a rectangle is
\n" ); document.write( "L + L + W + W
\n" ); document.write( "or
\n" ); document.write( "2L + 2W
\n" ); document.write( "or
\n" ); document.write( "2(L+W)
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\n" ); document.write( "Our equation is then:
\n" ); document.write( "2(L+W) = 100
\n" ); document.write( "But, we said (from the top) that L = 3W+3 so we substitute it in thus:
\n" ); document.write( "2(3W+3+W) = 100
\n" ); document.write( "2(4W+3) = 100
\n" ); document.write( "8W + 6 = 100
\n" ); document.write( "8W = 94
\n" ); document.write( "W = 11.75 (this is the width of the rectangle)
\n" ); document.write( "3W+3 = 3(11.75)+3 = 38.25 (this is the length of the rectangle)\r
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