document.write( "Question 147014: The sum of the digits of a two-digit number is 12. The number formed by interchanging the digits is 54 more than the orginal number. find the original number and its reversal. \r
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Algebra.Com's Answer #107357 by Fombitz(32388)\"\" \"About 
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Let the first digit in the original number be A.
\n" ); document.write( "Let the second digit in the original number be B.
\n" ); document.write( "1.\"A%2BB=12\"
\n" ); document.write( "The number can be represented as
\n" ); document.write( "\"10%2AA%2BB\"
\n" ); document.write( "The number with digits transposed would be
\n" ); document.write( "\"10%2AB%2BA\"
\n" ); document.write( "Putting all those together would yield,
\n" ); document.write( "\"10%2AB%2BA=10%2AA%2BB%2B54\"
\n" ); document.write( "\"-9A%2B9B=54\"
\n" ); document.write( "2.\"-A%2BB=6\"
\n" ); document.write( "Add eq.1 and eq.2 and solve for B.
\n" ); document.write( "\"A%2BB-A%2BB=12%2B6\"
\n" ); document.write( "\"2B=18\"
\n" ); document.write( "\"B=9\"
\n" ); document.write( "From 1,
\n" ); document.write( "\"A%2BB=12\"
\n" ); document.write( "\"A%2B9=12\"
\n" ); document.write( "\"A=3\"
\n" ); document.write( "Original number is 39.
\n" ); document.write( "Transposed number is 93.\r
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