document.write( "Question 146978: Five pencils and three erasers cost 65 cents. Three pencils and two erasers cost 40 cents. Find the cost of one pencil and the cost of one eraser.
\n" ); document.write( "So far I've got: 5p + 3e = .65 and 3p + 2e = .40 but don't know where to go from here to reach the answer.
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Algebra.Com's Answer #107319 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Look at it this way.
\n" ); document.write( "You have a system of equations.
\n" ); document.write( "Two equations with two unknowns, p and e.
\n" ); document.write( "You can solve the system to find p and e.
\n" ); document.write( "5p + 3e = .65
\n" ); document.write( "3p + 2e = .40
\n" ); document.write( "There are several methods you can use to solve this system of equations.
\n" ); document.write( "We'll use the substitution method.
\n" ); document.write( "First off, let's multiply both sides by 100 to get rid of the decimal.
\n" ); document.write( "1.\"500p%2B300e=65\"
\n" ); document.write( "2.\"300p%2B200e=40\"
\n" ); document.write( "You can use equation 1 to get 300p in terms of e and substitute into eq.2,
\n" ); document.write( "1.\"500p%2B300e=65\"
\n" ); document.write( "\"500p=65-300e\"
\n" ); document.write( "\"300p=%2865-300e%29%283%2F5%29\"Multiply both sides by (3/5).
\n" ); document.write( "\"300p=39-180e\"
\n" ); document.write( "Now substitute that value into equation 2 and solve for e.
\n" ); document.write( "2\"300p%2B200e=40\"
\n" ); document.write( "\"%2839-180e%29%2B200e=40\"
\n" ); document.write( "\"20e=1\"
\n" ); document.write( "\"e=0.05\"
\n" ); document.write( "Now you can use either equation to solve for p. I chose equation 2.
\n" ); document.write( "\"300p%2B200e=40\"
\n" ); document.write( "\"300p%2B200%280.05%29=40\"
\n" ); document.write( "\"300p%2B10=40\"
\n" ); document.write( "\"300p=30\"
\n" ); document.write( "\"p=0.10\"
\n" ); document.write( "So, the pencil costs a dime and the eraser costs a nickel.
\n" ); document.write( "You can check your answers by using your original equations.
\n" ); document.write( "5p + 3e = .65
\n" ); document.write( "5(0.10)+3(0.05)=.65
\n" ); document.write( "0.50+0.15=0.65
\n" ); document.write( "0.65=0.65
\n" ); document.write( "True
\n" ); document.write( "3p + 2e = .40
\n" ); document.write( "3(0.10)+2(0.05)=0.40
\n" ); document.write( "0.30+0.10=0.40
\n" ); document.write( "0.40=0.40
\n" ); document.write( "True
\n" ); document.write( "Your answers led to true statements.
\n" ); document.write( "They are good answers.
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