document.write( "Question 146975: A man invests a portion of $3,600 at 8% annual interest and the balance at 7%. If he receives $264 interest during the first year, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #107318 by checkley77(12844) ![]() You can put this solution on YOUR website! .08X+.07(3600-X)=264 \n" ); document.write( ".08X+252-.07X=264 \n" ); document.write( ".01X=264-252 \n" ); document.write( ".01X=12 \n" ); document.write( "X=12/.01 \n" ); document.write( "X=1200 INVESTED @ 8% \n" ); document.write( "3600-1200=2400 INVESTED @ 7% \n" ); document.write( "PROOF: \n" ); document.write( ".08*1200+.07*2400=264 \n" ); document.write( "96+168=264 \n" ); document.write( "264=264 \n" ); document.write( " |