document.write( "Question 146975: A man invests a portion of $3,600 at 8% annual interest and the balance at 7%. If he receives $264 interest during the first year, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #107318 by checkley77(12844)\"\" \"About 
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.08X+.07(3600-X)=264
\n" ); document.write( ".08X+252-.07X=264
\n" ); document.write( ".01X=264-252
\n" ); document.write( ".01X=12
\n" ); document.write( "X=12/.01
\n" ); document.write( "X=1200 INVESTED @ 8%
\n" ); document.write( "3600-1200=2400 INVESTED @ 7%
\n" ); document.write( "PROOF:
\n" ); document.write( ".08*1200+.07*2400=264
\n" ); document.write( "96+168=264
\n" ); document.write( "264=264
\n" ); document.write( "
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