document.write( "Question 146900: 9) Solve
\n" ); document.write( " 0.8x+8 <= 1.2x-9
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Algebra.Com's Answer #107286 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"0.8x%2B8%3C=1.2x-9\" Start with the given inequality.\r
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\n" ); document.write( "\n" ); document.write( "\"10%280.8x%2B8%29%3C=10%281.2x-9%29\" Multiply both sides by 10 to clear out the decimals.\r
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\n" ); document.write( "\n" ); document.write( "\"8x%2B80%3C=12x-90\" Distribute and multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"8x%3C=12x-90-80\" Subtract \"80\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"8x-12x%3C=-90-80\" Subtract \"12x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-4x%3C=-90-80\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-4x%3C=-170\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x%3E=%28-170%29%2F%28-4%29\" Divide both sides by \"-4\" to isolate \"x\". note: Remember, the inequality sign flips when we divide both sides by a negative number. \r
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\n" ); document.write( "\n" ); document.write( "\"x%3E=85%2F2\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x%3E=85%2F2\" \r
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\n" ); document.write( "\n" ); document.write( "Which approximates to \"x%3E=42.5\" \r
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