document.write( "Question 146888This question is from textbook
\n" ); document.write( ": Factor: 12y^3 + 16y^2 - 3y - 4 \n" ); document.write( "
Algebra.Com's Answer #107275 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"12y%5E3%2B16y%5E2-3y-4\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%2812y%5E3%2B16y%5E2%29%2B%28-3y-4%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"4y%5E2%283y%2B4%29-1%283y%2B4%29\" Factor out the GCF \"4y%5E2\" out of the first group. Factor out the GCF \"-1\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%284y%5E2-1%29%283y%2B4%29\" Since we have the common term \"3y%2B4\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"%282y%2B1%29%282y-1%29%283y%2B4%29\" Factor \"4y%5E2-1\" to get \"%282y%2B1%29%282y-1%29\" by use of the difference of squares.\r
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\n" ); document.write( "\n" ); document.write( "So \"12y%5E3%2B16y%5E2-3y-4\" factors to \"%282y%2B1%29%282y-1%29%283y%2B4%29\"
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