document.write( "Question 146881This question is from textbook Glencoe Algebra 1
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\n" ); document.write( "\n" ); document.write( "b/4+1/b=-5/3
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Algebra.Com's Answer #107265 by jim_thompson5910(35256)\"\" \"About 
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\"b%2F4%2B1%2Fb=-5%2F3\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"12b%28b%2Fcross%284%29%29%2B12cross%28b%29%281%2Fcross%28b%29%29=12b%28-5%2Fcross%283%29%29\" Multiply every term by the LCD 12b to clear the fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"3b%5E2%2B12=-20b\" Multiply and simplify\r
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\n" ); document.write( "\n" ); document.write( "\"3b%5E2%2B12%2B20b=0\" Add 20b to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"3b%5E2%2B20b%2B12=0\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "\"%28b%2B6%29%283b%2B2%29=0\" Factor the left side (note: if you need help with factoring, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:\r
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\n" ); document.write( "\n" ); document.write( "\"b%2B6=0\" or \"3b%2B2=0\" \r
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\n" ); document.write( "\n" ); document.write( "\"b=-6\" or \"b=-2%2F3\" Now solve for b in each case\r
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\n" ); document.write( "\n" ); document.write( "So our answers are \r
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\n" ); document.write( "\n" ); document.write( " \"b=-6\" or \"b=-2%2F3\" \r
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