document.write( "Question 146880This question is from textbook Glencoe Algebra 1
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\n" ); document.write( "x+3=-2/x
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Algebra.Com's Answer #107264 by jim_thompson5910(35256)\"\" \"About 
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\"x%2B3=-2%2Fx\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"x%2Ax%2Bx%2A3=cross%28x%29%28-2%2Fcross%28x%29%29\" Multiply every term by the LCD x to clear the fractions\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B3x=-2\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B3x%2B2=0\" Get all terms to the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%28x%2B1%29=0\" Factor the left side (note: if you need help with factoring, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:\r
\n" ); document.write( "\n" ); document.write( "\"x%2B2=0\" or \"x%2B1=0\" \r
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\n" ); document.write( "\n" ); document.write( "\"x=-2\" or \"x=-1\" Now solve for x in each case\r
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\n" ); document.write( "\n" ); document.write( "So our answers are \r
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\n" ); document.write( "\n" ); document.write( " \"x=-2\" or \"x=-1\" \r
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