document.write( "Question 146865: How do you solve |3x + 2| = 14, whats the answer? \n" ); document.write( "
Algebra.Com's Answer #107257 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"abs%283x%2B2%29=14\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "Break up the absolute value (remember, if you have \"abs%28x%29=a\", then \"x=-a\" or \"x=a\")\r
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\n" ); document.write( "\n" ); document.write( "\"3x%2B2=-14\" or \"3x%2B2=14\" Set the expression \"3x%2B2\" equal to the original value 14 and it's opposite -14\r
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\n" ); document.write( "\n" ); document.write( "Now lets focus on the first equation \"3x%2B2=-14\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x=-14-2\"Subtract 2 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"3x=-16\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-16%29%2F%283%29\" Divide both sides by 3 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=-16%2F3\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "Now lets focus on the second equation \"3x%2B2=14\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x=14-2\"Subtract 2 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"3x=12\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2812%29%2F%283%29\" Divide both sides by 3 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=4\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So the solutions to \"abs%283x%2B2%29=14\" are:\r
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\n" ); document.write( "\n" ); document.write( "\"x=-16%2F3\" and \"x=4\"\r
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