document.write( "Question 146848: perpendicular to y=2/5x-11 and has a y-intercept of 2 \n" ); document.write( "

Algebra.Com's Answer #107248 by nerdybill(7384) $\"\"$ $\"About$

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For a line to be perpendicular to another, their slopes must be \"negative reciprocal\".
\n" ); document.write( ".
\n" ); document.write( "Looking at:
\n" ); document.write( "y=(2/5)x-11
\n" ); document.write( "It is in the form of \"slope-intercept\" form of:
\n" ); document.write( "y = mx + b
\n" ); document.write( "where
\n" ); document.write( "m = slope
\n" ); document.write( "b = y-intercept
\n" ); document.write( ".
\n" ); document.write( "Therefore we KNOW that the slope is 2/5.
\n" ); document.write( "To find the \"negative reciprocal\":
\n" ); document.write( "(2/5)x = -1
\n" ); document.write( "x = -5/2
\n" ); document.write( ".
\n" ); document.write( "Now, we know the \"slope\" of the new line AND
\n" ); document.write( "the problem said, it has a \"y-intercept of 2\"
\n" ); document.write( "so, plug it all into:
\n" ); document.write( "y = mx + b
\n" ); document.write( "y = (-5/2)x + 2 \n" ); document.write( "

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