document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=146842>Question 146842</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many pounds of 20% copper alloy must be mixed with 600 lb. of a 30% copper alloy to make a 27.5% copper alloy? (must show alg)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107245 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107245\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .2x+600*.3=.275(600+x)<BR>\n" );
document.write( ".2x+180=165+.275x<BR>\n" );
document.write( ".2x-.275x=165-180<BR>\n" );
document.write( "-.075=-15<BR>\n" );
document.write( "x=-15/-.075<BR>\n" );
document.write( "x=200 lbs of 20% copper is needed.<BR>\n" );
document.write( "proof:<BR>\n" );
document.write( ".2*200+.3*600=.275*800<BR>\n" );
document.write( "40+180=220<BR>\n" );
document.write( "220=220 </SPAN>\n" );
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