document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=146757>Question 146757</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Golden Ratio.  The ancient Greeks thought that the most pleasing shape for a rectangle was one for which the ratio of the length to the width was 8 to 5, the golden ratio.  If the length of the rectangular painting is 2 feet longer than its width, then for which dimensions would the length and the width have the golden ratio? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107236 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107236\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L/w=8/5 golden ratio<BR>\n" );
document.write( "L=w+2<BR>\n" );
document.write( "(w+2)/w=8/5 Proportion<BR>\n" );
document.write( "5(w+2)=8w Multiply each side by the LCM (5w) to eliminate fractions.<BR>\n" );
document.write( "5w+10=8w<BR>\n" );
document.write( "3w=10<BR>\n" );
document.write( "w=10'/3=3' 4\"<BR>\n" );
document.write( "L=5' 4\"<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( " </SPAN>\n" );
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