document.write( "Question 146825: a painting is 3 inches longer than it is wide. it is set in a rectangular border that is 2 inches wider than the painting on each side. if the area of the border is 100 inch^2 what are the dimensions of the painting \n" ); document.write( "
Algebra.Com's Answer #107234 by edjones(8007)![]() ![]() You can put this solution on YOUR website! L*w=A \n" ); document.write( "L=w+3 for painting \n" ); document.write( "w*(w+3)=w^2+3w Area of the painting. \n" ); document.write( "(w+2)(w+5)=w^2+7w+10 Area of border and painting combined. \n" ); document.write( "w^2+7w+10-(w^2+3w)=100 \n" ); document.write( "w^2+7w+10-w^2-3w=100 \n" ); document.write( "4w+10=100 \n" ); document.write( "4w=90 \n" ); document.write( "w=22.5\" \n" ); document.write( "L=25.5\" \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " \n" ); document.write( " |