document.write( "Question 146803: Solve:\r
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document.write( "One number is 11 less than a second number. Twice the second number is 52 more than 4 times the first. Find the two numbers. \n" );
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Algebra.Com's Answer #107226 by 24HoursTutor.com(40)![]() ![]() ![]() You can put this solution on YOUR website! Let the two numbers be x and y. Now, we understand from the first sentence that the first number which we have assumed to be x is 11 less than the second number y. Which means that if we add eleven to the first number we will get the second number. Thus, we get the equation as : \r \n" ); document.write( "\n" ); document.write( " x + 11 = y\r \n" ); document.write( "\n" ); document.write( "Now, the second sentence tells us that twice the second number, y in our case is equal to 4 times the first number(x) and 52 more. So we have :\r \n" ); document.write( "\n" ); document.write( " 2y = 52 + 4x\r \n" ); document.write( "\n" ); document.write( "Since we have an equation for y , we substitute it in this equation to get :\r \n" ); document.write( "\n" ); document.write( " 2(x+11) = 52 + 4x \n" ); document.write( " 2x + 22 = 52 + 4x \n" ); document.write( " 2x - 4x = 52 -22 \n" ); document.write( " - 2x = 30 \n" ); document.write( " x = 30 / -2 \n" ); document.write( " x = -15\r \n" ); document.write( "\n" ); document.write( "Now, since we have the value of x, we can get the value of y by : \n" ); document.write( " y = x + 11 \n" ); document.write( " y = -15 + 11 \n" ); document.write( " y = -4\r \n" ); document.write( "\n" ); document.write( "Ans.: The first number is -15 and the second number is -4. You can cross check your answer by substituting the value in both the equations and seeing if they still hold true.\r \n" ); document.write( "\n" ); document.write( "The above question is solved by one of the experts from 24HoursTutor.com \n" ); document.write( "We provide live 1:1 online homework help \n" ); document.write( "1. 24X7 tutors available \n" ); document.write( "2. Certified tutors \n" ); document.write( "3. Only for $9.99/hr \n" ); document.write( " |