document.write( "Question 146803: Solve:\r
\n" ); document.write( "\n" ); document.write( "One number is 11 less than a second number. Twice the second number is 52 more than 4 times the first. Find the two numbers.
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Algebra.Com's Answer #107226 by 24HoursTutor.com(40)\"\" \"About 
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Let the two numbers be x and y. Now, we understand from the first sentence that the first number which we have assumed to be x is 11 less than the second number y. Which means that if we add eleven to the first number we will get the second number. Thus, we get the equation as : \r
\n" ); document.write( "\n" ); document.write( " x + 11 = y\r
\n" ); document.write( "\n" ); document.write( "Now, the second sentence tells us that twice the second number, y in our case is equal to 4 times the first number(x) and 52 more. So we have :\r
\n" ); document.write( "\n" ); document.write( " 2y = 52 + 4x\r
\n" ); document.write( "\n" ); document.write( "Since we have an equation for y , we substitute it in this equation to get :\r
\n" ); document.write( "\n" ); document.write( " 2(x+11) = 52 + 4x
\n" ); document.write( " 2x + 22 = 52 + 4x
\n" ); document.write( " 2x - 4x = 52 -22
\n" ); document.write( " - 2x = 30
\n" ); document.write( " x = 30 / -2
\n" ); document.write( " x = -15\r
\n" ); document.write( "\n" ); document.write( "Now, since we have the value of x, we can get the value of y by :
\n" ); document.write( " y = x + 11
\n" ); document.write( " y = -15 + 11
\n" ); document.write( " y = -4\r
\n" ); document.write( "\n" ); document.write( "Ans.: The first number is -15 and the second number is -4. You can cross check your answer by substituting the value in both the equations and seeing if they still hold true.\r
\n" ); document.write( "\n" ); document.write( "The above question is solved by one of the experts from 24HoursTutor.com
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