document.write( "Question 146815This question is from textbook
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document.write( ": Find k so that the line through (4,-1) and (k,2) is
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document.write( "a. parallel to 2x + 3y = 6
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document.write( "b. perpendicular to 5x - 2y = -1 \n" );
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Algebra.Com's Answer #107217 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Find k so that the line through (4,-1) and (k,2) is \n" ); document.write( "a. parallel to 2x + 3y = 6 \n" ); document.write( "b. perpendicular to 5x - 2y = -1 \n" ); document.write( "------------------ \n" ); document.write( "a. Put in form y = mx+b to find the slope m \n" ); document.write( "y = (-2/3)x + 2 \n" ); document.write( "m = -2/3 \n" ); document.write( "To be parallel, the line has to have the same slope. \n" ); document.write( "m = (y2-y1)/(x2-x1) \n" ); document.write( "-2/3 = (2 - (-1))/(k - 4) \n" ); document.write( "-2/3 = 3/(k-4) \n" ); document.write( "-2(k-4) = 9 \n" ); document.write( "-2k+8 = 9 \n" ); document.write( "2k=-1 \n" ); document.write( "k = -1/2 \n" ); document.write( "Check: (2 + 1)/((-1/2) - 4) = 3/(-4.5) = -2/3 \n" ); document.write( "------------------ \n" ); document.write( "b. The slope m of 5x - 2y = -1 is 5/2. \n" ); document.write( "To be perpendicular, the slope is the negative inverse, -2/5. \n" ); document.write( "m = (y2-y1)/(x2-x1) \n" ); document.write( "-2/5 = (2+1)/(k-4) \n" ); document.write( "Cross multiply \n" ); document.write( "-2(k-4) = 5*3 \n" ); document.write( "-2k+8 = 15 \n" ); document.write( "2k = -7 \n" ); document.write( "k = -7/2 \n" ); document.write( "Check (2 + 1)/(-3.5 -4) = 3/(-7.5) = -2/5\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |