document.write( "Question 146812: the sum of the reciprocals of two consecutive odd integers is 20/99. find the two integers.\r
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document.write( "pleasee helpp \n" );
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Algebra.Com's Answer #107214 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! 1/n + 1/(n+2) = 20/99 \n" ); document.write( "Multiply by n(n+2) \n" ); document.write( "n+2 + n = 20n(n+2)/99 \n" ); document.write( " \n" ); document.write( "Multiply by 99 \n" ); document.write( " \n" ); document.write( "Put in quadratic form \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-1.1 is not a positive integer, so discard it. \n" ); document.write( "n = 9 \n" ); document.write( "n+2 = 11 \n" ); document.write( "It does work, 1/9 + 1/11 = 20/99 \n" ); document.write( " |