document.write( "Question 146812: the sum of the reciprocals of two consecutive odd integers is 20/99. find the two integers.\r
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Algebra.Com's Answer #107214 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
1/n + 1/(n+2) = 20/99
\n" ); document.write( "Multiply by n(n+2)
\n" ); document.write( "n+2 + n = 20n(n+2)/99
\n" ); document.write( "\"2n%2B2+=+%2820n%5E2+%2B+40n%29%2F99\"
\n" ); document.write( "Multiply by 99
\n" ); document.write( "\"198n+%2B+198+=+20n%5E2+%2B+40n\"
\n" ); document.write( "Put in quadratic form
\n" ); document.write( "\"20n%5E2+-+158n+-+198+=+0\"
\n" ); document.write( "\"10n%5E2+-+79n+-+99+=+0\"
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"10x%5E2%2B-79x%2B-99+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-79%29%5E2-4%2A10%2A-99=10201\".
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\n" ); document.write( " Discriminant d=10201 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--79%2B-sqrt%28+10201+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-79%29%2Bsqrt%28+10201+%29%29%2F2%5C10+=+9\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-79%29-sqrt%28+10201+%29%29%2F2%5C10+=+-1.1\"
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\n" ); document.write( " Quadratic expression \"10x%5E2%2B-79x%2B-99\" can be factored:
\n" ); document.write( " \"10x%5E2%2B-79x%2B-99+=+%28x-9%29%2A%28x--1.1%29\"
\n" ); document.write( " Again, the answer is: 9, -1.1.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+10%2Ax%5E2%2B-79%2Ax%2B-99+%29\"

\n" ); document.write( "\n" ); document.write( "-1.1 is not a positive integer, so discard it.
\n" ); document.write( "n = 9
\n" ); document.write( "n+2 = 11
\n" ); document.write( "It does work, 1/9 + 1/11 = 20/99
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