document.write( "Question 22192: (8/27)to the power of 2/3 \n" ); document.write( "

Algebra.Com's Answer #10721 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
The \"2\" in your problem tells you to \"square\" something.\r
\n" ); document.write( "\n" ); document.write( "The \"3\" in your problem is in the denominator of your
\n" ); document.write( "exponent and tells you to \"take the cube root\" of something.\r
\n" ); document.write( "\n" ); document.write( "You may carry out these instructions in either order and
\n" ); document.write( "still get the correct answer. I'll show you how it works
\n" ); document.write( "both ways.\r
\n" ); document.write( "\n" ); document.write( "1st: (8/27)^(2/3)\r
\n" ); document.write( "\n" ); document.write( " squaring first you get 64/729
\n" ); document.write( " now taking the cube root you get 4/9\r
\n" ); document.write( "\n" ); document.write( "2nd: (8/27)^(2/3)
\n" ); document.write( " taking the cube root you get 2/3
\n" ); document.write( " now squaring the result you get 4/9\r
\n" ); document.write( "\n" ); document.write( "The 2nd way is the better way to do it because it keeps
\n" ); document.write( "the numbers smaller.\r
\n" ); document.write( "\n" ); document.write( "Good luck,
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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