document.write( "Question 146602: An investment of 5600 is made at an annual simple interest rate of 6.5%. How much additional money must be invested at an annual simple interest rate of 9% so that the toatl interest earned is 8% of the total investement \n" ); document.write( "
Algebra.Com's Answer #107200 by checkley77(12844)\"\" \"About 
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5600*.065+.09x=.08(5600+x)
\n" ); document.write( "364+.09x=448+.08x
\n" ); document.write( ".09x-.08x=448-364
\n" ); document.write( ".01x=84
\n" ); document.write( "x=84/.01
\n" ); document.write( "x=8,400 invested @ 9% will stiafy the need.
\n" ); document.write( "proof:
\n" ); document.write( "5600*.065+.09*8,400=.08(5600+8,400)
\n" ); document.write( "364+756=.08*14,000
\n" ); document.write( "1,120=1,120
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