document.write( "Question 146769:
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Algebra.Com's Answer #107180 by jim_thompson5910(35256)\"\" \"About 
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Let x=width and y=length\r
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\n" ); document.write( "\n" ); document.write( "Since \"The length of a rectangle is five less than twice the width\", this means that \"y=2x-5\". Also, because \"The area is 42 square yards\", this tells us that the area equation is \"A=x%2Ay\" which becomes \"42=x%2Ay\"\r
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\n" ); document.write( "\n" ); document.write( "\"42=x%2Ay\" Start with the second equation\r
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\n" ); document.write( "\n" ); document.write( "\"42=x%2A%282x-5%29\" Plug in \"y=2x-5\"\r
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\n" ); document.write( "\n" ); document.write( "\"42=2x%5E2-5x\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"42-2x%5E2%2B5x=0\" Get all terms to the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-2x%5E2%2B5x%2B42=0\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic equation in the form of \"ax%5E2%2Bbx%2Bc\" where \"a=-2\", \"b=5\", and \"c=42\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%285%29+%2B-+sqrt%28+%285%29%5E2-4%28-2%29%2842%29+%29%29%2F%282%28-2%29%29\" Plug in \"a=-2\", \"b=5\", and \"c=42\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+25-4%28-2%29%2842%29+%29%29%2F%282%28-2%29%29\" Square \"5\" to get \"25\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+25--336+%29%29%2F%282%28-2%29%29\" Multiply \"4%28-2%29%2842%29\" to get \"-336\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+25%2B336+%29%29%2F%282%28-2%29%29\" Rewrite \"sqrt%2825--336%29\" as \"sqrt%2825%2B336%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+361+%29%29%2F%282%28-2%29%29\" Add \"25\" to \"336\" to get \"361\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+361+%29%29%2F%28-4%29\" Multiply \"2\" and \"-2\" to get \"-4\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+19%29%2F%28-4%29\" Take the square root of \"361\" to get \"19\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B+19%29%2F%28-4%29\" or \"x+=+%28-5+-+19%29%2F%28-4%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2814%29%2F%28-4%29\" or \"x+=++%28-24%29%2F%28-4%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+-7%2F2\" or \"x+=+6\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the widths are \"x+=+-7%2F2\" or \"x+=+6\" \r
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\n" ); document.write( "\n" ); document.write( "However, since a negative width is not possible, this means that the only answer for the width is \"x+=+6\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=2x-5\" Go back to the first equation\r
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\n" ); document.write( "\n" ); document.write( "\"y=2%286%29-5\" Plug in \"x+=+6\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=7\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "So the width is 6 yards and the length is 7 lards
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