document.write( "Question 146738: Can you help me solve this Using augmented matrices to solve the following 2 x 2 systems of equations. Show all work.\r
\n" ); document.write( "\n" ); document.write( "1. 3x + 4y = 11
\n" ); document.write( " x + 3y = 2\r
\n" ); document.write( "\n" ); document.write( "
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Algebra.Com's Answer #107168 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
If you started with:
\n" ); document.write( " 3x + 4y = 11
\n" ); document.write( " x + 3y = 2
\n" ); document.write( ".
\n" ); document.write( "The \"coefficient matrix\" is:
\n" ); document.write( "3 4
\n" ); document.write( "1 3
\n" ); document.write( ".
\n" ); document.write( "The determinant of the \"coefficient matrix\" is:
\n" ); document.write( "(3*3) - (1*4) = 9 -4 = 5
\n" ); document.write( ".
\n" ); document.write( "The 'x' matrix is:
\n" ); document.write( "11 4
\n" ); document.write( " 2 3
\n" ); document.write( ".
\n" ); document.write( "The determinant of the 'x' matrix is:
\n" ); document.write( "(11*3)-(2*4) = 33 -8 = 25
\n" ); document.write( ".
\n" ); document.write( "The 'y' matrix is:
\n" ); document.write( "3 11
\n" ); document.write( "1 2
\n" ); document.write( ".
\n" ); document.write( "The determinant of the 'y' matrix is:
\n" ); document.write( "(2*3)-(1*11) = 6 -11 = -5
\n" ); document.write( ".
\n" ); document.write( "Solution for 'x' is \"det of x\"/\"det of coefficient\":
\n" ); document.write( "25/5 = 5
\n" ); document.write( ".
\n" ); document.write( "Solution for 'y' is \"det of y\"/\"det of coefficient\":
\n" ); document.write( "-5/5 = -1
\n" ); document.write( ".
\n" ); document.write( "Our solution is (x,y) = (5,-1)
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\n" ); document.write( "To check, plug it back into:
\n" ); document.write( " x + 3y = 2
\n" ); document.write( " 5 + 3(-1) = 2
\n" ); document.write( " 5 - 3 = 2
\n" ); document.write( " 2 = 2 (check)
\n" ); document.write( "and
\n" ); document.write( " 3x + 4y = 11
\n" ); document.write( " 3(5) + 4(-1) = 11
\n" ); document.write( " 15 - 4 = 11
\n" ); document.write( " 11 = 11 (check)\r
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