document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=146545>Question 146545</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jennifer traveled at a constant speed on an old road for 160 miles. She then traveled 5 miles per hour faster on a newer road for 90 miles. If she drove for 6 hours, find the car's speed for the part of the trip that was traveled on the new road.\r<BR>\n" );
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document.write( "While you might find the speed on the old road in your calculations, do not include that in your answer. Do not include units in your answer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107164 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107164\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let old road speed be s, new road speed be s+5; d=160+90, t=6<BR>\n" );
document.write( "d=ts<BR>\n" );
document.write( "d/s=t<BR>\n" );
document.write( "160/s + 90/(s+5)=6<BR>\n" );
document.write( "160(s+5)+90s=6s(s+5) Multiply each side by the LCM to eliminate fractions.<BR>\n" );
document.write( "160s+800+90s=6s^2+30s<BR>\n" );
document.write( "6s^2+30s-160s-90s-800=0 Subtract the left side from the right.<BR>\n" );
document.write( "6s^2-220s-800=0<BR>\n" );
document.write( "2(3s^2-110s-400)=0<BR>\n" );
document.write( "(s-40)(3s+10)=0 Factor (or use the quadratic formula)<BR>\n" );
document.write( "s=40<BR>\n" );
document.write( "s+5=45 mph answer<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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