document.write( "Question 146732: one canned juice drink 30% orange juice, another is 10% orange juice. How many liters of each should be mixed togethr in order to get 20L that is 19% orange juice.\r
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document.write( "How many liters of the 10% orange juice should be in the mixture? \n" );
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Algebra.Com's Answer #107154 by tutorcecilia(2152)![]() ![]() You can put this solution on YOUR website! x + y = 20 \n" ); document.write( "So, y = 20-x \n" ); document.write( "And, \n" ); document.write( ".30x + .10y = (20)(.19) \n" ); document.write( ".30x + .10 (20-x) = 3.8 \n" ); document.write( ".30x + 2 - .10x = 3.8 \n" ); document.write( ".30x - .10x = 3.8 - 2 \n" ); document.write( ".20x=1.8 \n" ); document.write( "x=1.8/.20 \n" ); document.write( "x=9 liters at 30% \n" ); document.write( "So, \n" ); document.write( "x+y=20 \n" ); document.write( "9+y=20 \n" ); document.write( "y=20-9 \n" ); document.write( "y=11 liters at 10% \n" ); document.write( " |