document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=146723>Question 146723</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "find the shortest distance between the parallel lines with equations 5x-12y+33=0 and 5x-12y-6=0 <BR>\n" );
document.write( "A.3<BR>\n" );
document.write( "B.39<BR>\n" );
document.write( "c.27/5<BR>\n" );
document.write( "D.27/13<BR>\n" );
document.write( "E.n/a\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #107149 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=107149\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First you need to find the line that is perpendicular to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5x-12y%2B33=0 ALIGN=MIDDLE  ALT=\"5x-12y%2B33=0\"   DISABLED_style= \"max-width:90%; height:auto;\" > (it will also be perpendicular to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5x-12y-6=0 ALIGN=MIDDLE  ALT=\"5x-12y-6=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >)\r<BR>\n" );
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document.write( "Now this line will intersect with both equations 5x-12y+33=0 and 5x-12y-6=0. So you want to find the points of intersection. From there, simply use the distance formula <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d=sqrt%28%28x%5B2%5D-x%5B1%5D%29%5E2%2B%28y%5B2%5D-y%5B1%5D%29%5E2%29 ALIGN=MIDDLE  ALT=\"d=sqrt%28%28x%5B2%5D-x%5B1%5D%29%5E2%2B%28y%5B2%5D-y%5B1%5D%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > to find the distance between the two points of intersection. I hope that's enough to get you started. </SPAN>\n" );
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